Does the order in which wine is presented make a difference? several choices of wine are presented one at a time and in sequence, and the subject is then asked to choose the preferred wine at the end of the sequence. in this study, subjects were asked to taste two wine samples in sequence. both samples given to a subject were the same wine, although subjects were expecting to taste two different samples of a particular variety. of the 32 subjects in the study, 22 selected the wine presented first, when presented with two identical wine samples. how large a sample would be needed to obtain margin of error ±0.05 in the study of choice order for tasting wine? let ^p=0.6875 .

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

(x) - (y) = (1 + 4i)

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6

p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder