Find z such that 29 % 29% of all observations from a standard normal distribution are greater than z . z. (enter your answer rounded to two decimal places.)

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Find z such that 29 % 29% of all observations from a standard normal distribution are greater than z .

This is the value of Z which has a pvalue of 1-0.29 = 0.71.

Looking at the z table, we have that this is .

answer: its the third option.

step-by-step explanation:

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y=sec x is the correct answer

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