Mathematics, 16.01.2020 20:31 Lacey9148

Which is the equation of a parabola with a directrix at y = 2 and a focus at (5, 0).
y = one fourth(x − 5)2 + 1
y = one fourth(x + 1)2 − 5
y = −one fourth(x + 1)2 − 5
y = −one fourth(x − 5)2 + 1

Answers: 1

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Which is the equation of a parabola with a directrix at y = 2 and a focus at (5, 0).
y = one...

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Which is the equation of a parabola with a directrix at y = 2 and a focus at (5, 0). y = one fourth(x − 5)2 + 1 y = one fourth(x + 1)2 − 5 y = −one fourth(x + 1)2 − 5 y = −one fourth(x − 5)2 + 1

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Another question on Mathematics

Which is the equation of a parabola with a directrix at y = 2 and a focus at (5, 0).
y = one fourth(x − 5)2 + 1
y = one fourth(x + 1)2 − 5
y = −one fourth(x + 1)2 − 5
y = −one fourth(x − 5)2 + 1