the perimeter of rectangle a is three times that of rectangle b. rectangle b
is 4 cm long and 6 cm wide. given that rectangle a and rectangle b are
similar, what is the perimeter of rectangle a?
a. 72 cm
b. 60 cm
c. 20 cm
d. 24 cm

Step-by-step explanation:

Rectangle B :

P = 2(L + W)

L = 4

W = 6

P = 2(4 + 6)P = 2(10)...P = 20 cm

so the perimeter of rectangle B is 20 cm

perimeter of rectangle A is 3 times bigger...

so perimeter of rectangle A is : (3 * 20) = 60 cm <==

another way to do this is if rectangle A is 3 times bigger, then the length and width are 3 times bigger too

so if rectangle B has a length of 4 cm, then rectangle A has a length of

(4 * 3) = 12 cm

and if rectangle B has a width of 6 cm, then rectangle A has a width of

(6 * 3) = 18 cm

so rectangle A perimeter is :

P = 2(L + W)

L = 12

W = 18

P = 2(12 + 18)...P = 2(30)P = 60 cm <===

either way u choose to do it will give u the same answer

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )