Which triangle is similar to △abc if sin(a) = one-fourth, cos(a) = startfraction startroot 15 endroot over 4 endfraction, and tan(a) = startfraction 1 over startroot 15 endroot endfraction? triangle r s t is shown. angle r s t is a right angle. the length of hypotenuse r t is 13, the length of s t is 12, and the length of r s is 5. triangle i j k is shown. angle i j k is a right angle. the length of hypotenuse i k is 3 startroot 15 endroot, the length of j k is 3, and the length of j i is 12. triangle m l n is shown. angle m n l is a right angle. the length of hypotenuse l m is startroot 15 endroot, the length of m n is 3, and the length of l n is startroot 6 endroot. triangle x y z is shown. angle y z x is a right angle. the length of hypotenuse x y is 24, the length of x z is 6 startroot 15 endroot, and the length of z y is 6.

The answer is D) triangle XYZ

The answer is D) triangle XYZ

Step-by-step explanation:

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.