14. use the given degree of confidence and sample data to construct a confidence interval for the population mean. assume that the population has a normal distribution.
n=10, x=8.7, s=3.3, 95% confidence
i know the answer is 6.34< μ< 11.06 but i dont know how to get there

Step-by-step explanation:

Confidence interval = mean ± margin of error

CI = μ ± ME

The mean is μ = 8.7.

Margin of error = critical value × standard error

ME = CV × SE

At 95% confidence and 9 degrees of freedom, CV = 2.262.

SE = s / √n

SE = 3.3 / √10

SE = 1.04

The margin of error is:

ME = 2.262 × 1.04

ME = 2.36

CI = 8.7 ± 2.36

CI = (6.34, 11.06)

594 square inches

step-by-step explanation:

vote !

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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