Solve a triangle with a = 32. b = 38, and c = 46.
a. a = 43.5°: b = 54.8°: c= 81.70
b. a = 54.3º: b = 54.8°; c = 81.70
c. a = 43.5°: b = 66.5°; c = 81.7
d. a = 43.50: b = 54.8°; c = 78.4°

Using the law of cosines:

Angle A

a^2 = b^2 + c^2 - 2 * b * c * cos(Angle A)

32^2 = 38^2 + 46^2 - 2 * 38 * 46 * cos(Angle A)

1024 = 1444 + 2116 - 3496 * cos(Angle A)

3496 * cos(Angle A) = 1444 + 2116 - 1024

3496 * cos(Angle A) = 2536

cos(Angle A) = 2536 / 3496

Angle A = arccos(2536 / 3496)

Angle A = 43.5 degrees.

Using the same steps calculate angle b and angle c ( rearrange the formula to have b^2 and c^2 equal to:

Angle b = 54.8 degrees

Angle C = 81.7 degrees.

The answer is A. A = 43.5°: B = 54.8°: C= 81.70

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the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).