Marcos and 16 coins in nickels and quarters. he has 3 more quarters than nickels. write the system of equations and solve to find the number of nickels and the number of quarters marcos has.

There is typo error in the question. The total number of coins will be 15.

There are 6 nickels and 9 quarters.

Step-by-step explanation:

Let 'n' be number of nickels and 'q' be number of quarters.

Given:

Marcos has 15 coins in total.

Marcos has 3 more quarters than nickels.

So, as per question,

Total coins = Number of nickels + Number of quarters.

Framing in equation form, we get:

------------------ (1)

Now, Marcos has 3 more quarters than nickels. So, framing in equation form, we get:

-------------------- (2)

Substitute the value of 'q' from equation (2) to equation (1). This gives,

Therefore, the number of nickels are 6.

Now, number of quarters = 6 + 3 = 9

So, there are 6 nickels and 9 quarters.

i do not know this sorry : (

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers