Abox contains 5 plain pencils and 5 pens. a second box contains 3 pencils and 1 crayon. one item from each box is chosen at random what is the probability that a pen from the first box and a crayon from the second box are selected

0.75

Step-by-step explanation:

OK maths is always about looking at thing simply, one by one.

Let us look at the first box. There r 5 pencils and 5 pens. So what is the probability of getting a pen from first box? First there r total of 10 things in the first box. Probability of getting a pen from that box? It is 5÷10 which is number of favorable pitcomes to pen ÷ total number of outcomes which is 10.

Now the second box. There r 1 crayon and 3 pencils. Total of 4 outcomes(3plus1).

So probablilty of getting a crayon from second box is number of favorable outcomes to crayon ÷ total number of outcomes which is 4=1÷4

Now add the first probability of getting a pen from first box and probability of getting a crayon from second box. This is because it's given in the question to find out the probability of getting a pen AND a crayon which means first find the probability of pen and crayon seperatly and then add them.

Now add those 2 probabilities together which is 5÷10 plus 1÷4 then we will get 0.75.

I hope this helps u. Pls follow me and like it.

you're missing vital information, add to it so we can solve this problem for you.

step-by-step explanation: