Women’s weights are normally distributed with a mean given by µ = 143 lb and a standard deviation given by σ = 29 lb. find the third decile, d3, which separates the bottom 30% from the top 70%

127.7924

Step-by-step explanation:

Given that women’s weights are normally distributed with a mean given by µ = 143 lb and a standard deviation given by σ = 29 lb.

Let x be the weight of women

X is N (143, 29)

Or is N(0,1)

From standard normal distribution table we can find D3 i.e. 30th percentile and then convert suitably to X score

30th percentile in Normal =-0.5244

Corresponding X = Mean -0.5244 * std deviation

=

The third decile, D3, which separates the bottom 30% from the top 70%.___is 127.7924____

its c or d   take a lucky guess my dude

a .4y4

hope this !