James reads that 1 out of 6 eggs contains salmonella bacteria. so he never uses more than 5 eggs in cooking. if eggs do or don't contain salmonella independently of each other, the number of contaminated eggs when james uses 5 chosen at random has the distributiona. binomial with n = 6 and p = 1/6.b. binomial with n = 5 and p = 1/6.c. binomial with n = 5 and p = 1/5.

B. binomial with n = 5 and p = 1/6

Step-by-step explanation:

Given that James reads that 1 out of 6 eggs contains salmonella bacteria.

So he never uses more than 5 eggs in cooking.

If eggs do or don't contain salmonella independently of each other, then

probability for any one egg to contain salmonella bacteria is the constant 1/6.

Also there are only two outcomes, either bacteria present or not.

Hence the  number of contaminated eggs when James uses 5 chosen at random has the distribution is Binomial

Here n = no of trials = no of eggs he uses = 5

Probability = 1/6

So option B is right.

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.