Eliza reads of her book on monday. on tuesday and wednesday combined,
she reads three times as much as she reads on monday. the expression
1/7r+3(1/7r)can be used to determine the number of pages eliza reads on
monday, tuesday, and wednesday combined. the variable r represents the total
umber of pages in the book.

Part A: 204 pages

Part B: 232 pages. 28 pages more.

Step-by-step explanation:

Eliza reads of her book on Monday by pages, where r is the total number of pages in the book.

On Tuesday and Wednesday combined,  she reads three times as much as she reads on Monday i.e. pages.

So, combining Monday, Tuesday and Wednesday she reads number of pages.

Part A: If Eliza's book has a total of 357 pages then combining Monday, Tuesday and Wednesday she reads pages.

Part B: If Renee Reads the same fraction of a different book over the same period of time as Eliza, then if Renee's book has a total of 406 pages then combining Monday, Tuesday and Wednesday she reads a total of   pages.

She reads (232 - 204) = 28 more pages than Eliza. (Answer)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.