(a) the position of a particle at time t is s(t) = t^3 + t. compute the average velocity over the time interval [7, 12].(b) estimate the instantaneous velocity at t = 7. (round your answer to the nearest whole number)

Step-by-step explanation:

a) Average velocity is the ratio of displacement to time.

   We have

              s(t) = t³ + t

    t is in between 7 and 12

             s(7) =  7³ + 7 = 350

              s(12) = 12³ + 12 = 1740

    Displacement = 1740 - 350 = 1390

   Time = 12 - 7 = 5

  Displacement =  Average velocity x time

  1390 = Average velocity x 5

  Average velocity = 278 units

b) s(t) = t³ + t

   Differentiating

         v(t) = 3t² + 1

  At t = 7

          v(t) = 3 x 7² + 1 = 148 units

  Instantaneous velocity at t = 7 seconds is 148 units

tigers

step-by-step explanation:

cougars 12/10 (12-10 = 2)

bobcats 20/10 (20-10 =10)

bulldogs 8/5 (8-5 =3)

tigers 3/5 (3-5 =-2)

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116