Arectangular packet of drink has a width that is 2 cm less than its length.
its height is 4 cm more than its length.
(a) it is given that the length of the packet is m cm. write down an expression,
in terins of m, for the total surface area of the packet.
[2]

Step-by-step explanation:

Given that the length of the packet is cm.

Then the width being 2cm less than the length becomes and the height being 4 cm more than its length becomes

The total surface area of the rectangular packet is given by:

We expand to get:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer: ♡♡♡♡♡♡♡♡♡♡

step-by-step explanation: