Akite is flying above the ground
at the end of a 100 feet of string.
if the angle of elevation of the
kite is 65°, how high above the
ground is the kite flying?

The height of the kite above the ground is 90.63 feet.

Step-by-step explanation:

The angle of elevation of the kite is (θ) 65°.

The distance between the kite and its end is (hypotenuse)100 feet.

To find the height (x) of the kite flying above the ground.

we know that sin(θ) =.

sin 65°=

sin 65° =  0.90631.

0.90631 ×100=x.

90.63=x.

∴The height of the kite above the ground is 90.63 feet.

< 6 cm to > 26 cm i believe

step-by-step explanation:

i use my brain for prombles like this maybe you could try it

step-by-step explanation: