At an animal shelter the number of dog adoptions one weekend was 10 less than 3 times the number of cat adoptions. the number of cat adoptions plus twice the number of dog adoptions was 8

Let d= number of dog adoptions, and c= number of cat adoptions.

Create equations:

d=3c-10
c+2d=8

Solve the equations simultaneously:

c+2(3c-10)=8
c+6c-20=8
7c=28
c=4

d=3(4)-10
d=12-10
d=2

Therefore there were 4 cat adoptions and 2 dog adoptions.

Please give brainliest.

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