Find the solutions to the following linear-quadratic systems algebraically. select the ordered pair that is one of the correct solutions from among the choices below.
y = x² +3x + 8
y = 2x + 10

(-2, 6)
(0, 8)
(0,10)
(2, 14)

(-2, 6)

Step-by-step explanation:

we have

----> equation A

----> equation B

equate equation A and equation B

The formula to solve a quadratic equation of the form

is equal to

in this problem we have

so

substitute in the formula

Find the values of y

For x=1

For x=-2

therefore

The solutions are (1,12) and (-2,6)

i dont know

step-by-step explanation:

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.