Circle c lies on the coordinate plane with its center at (2,−16).
point a(2,−13) lies on circle c.
which equation verifies that the point p(−1,−16) lies on circle c?
(2−1)2+(−16−16)2=(2+2)2+(−16−13)2 (2+16)2+(−1+16)2=(2+2)2+(−16−13)2 (2+1)2+(−16+16)2=(2−2)2+(−16+13)2 (2−16)2+(2−13)2=(2−16)2+(−1−16)2

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

too many. (jk)

31 v bucks

step-by-step explanation:

since you bought 25 on friday and 6 on tuesday, you can just add them up.

25+6=31

check your work.

31-6=25

i hope this !

-yand3r3