which pair of functions is not a pair of inverse functions?

a. f(x)= x+1/6 and g(x)= 6x-1

b. f(x)= x-4/19 and g(x)= 19x+4

c. f(x)= x5 and g(x)= 5√x

d. f(x)= x/x + 20 and g(x)= 20x/x-1
you!

Option in D is not an inverse function.

Step-by-step explanation:

A. Say,

⇒ 6y = x + 1

⇒ x = 6y - 1

Here, g(x) = 6x - 1, if g(x) is the inverse function of f(x).

B. Let us assume,

⇒ 19y = x - 4

⇒ x = 19x + 4

If g(x) is the inverse function of f(x), then, g(x) = 19x + 4

C. Let

⇒

Here, , if g(x) is the inverse function of f(x).

D. Let

⇒ yx + 20y = x

⇒ x(y - 1) = - 20y

⇒

Now, if g(x) is the inverse function of f(x), then,

Therefore, option in D is not an inverse function. (Answer)

answer:

your answer is: c. 196 7/8 in^3.