Drawing a red marble from a bag of six red and 4 blue replacing it and then drawing a blue marble

The probability of picking a red marble and a blue marble = 6/25

Step-by-step explanation:

Here, the question is INCOMPLETE.

What is the probability of this independent event. Drawing a red marble from a bag of 6 red and 4 blue marbles, replacing it, and then drawing a blue marble.

Here, total number of red marble in bag = 6

total number of blue marble in bag = 4

So, total marbles in the bag = 6 + 4 = 10 marbles

Now,if E : Any given event, then

So, here

⇒ P(a Red ball)  = 3/5    ...... (1)

Now, if the picked marble is REPLACED, then total marbles in the bag  = 10

So, here

⇒ P(a Blue marble)  = 2/5    ...... (2)

So, the probability of picking a red marble and a blue marble AFTER REPLACING

=P(a Red marble) x P(a Blue marble)  = 3/5 x 2/5  = 6 /25

Hence, the probability of picking a red marble and a blue marble = 6/25

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.