Aferry will safely accommodate 68 tons of passenger cars. assume that the mean weight of a passenger car is 1.8 tons with standard deviation 0.5 tons. if a random sample of 35 cars are loaded onto the ferry, what is the probability that the maximum safe weight will be exceeded?

Step-by-step explanation:

We want the probability that the 35 cars are loaded onto the ferry. Therefore:

Since  

μ=1.8  and  σ=0.5  we have:

P(X<35 )=P ( X−μ<35−1.8 )=P((X−μ)/σ<(35−1.8)/0.5)

Since  

(x−μ)/σ=Z and  

we have:

Use the standard normal table to conclude that:

y=mx+

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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