What quantity of 72% acetic acid solution must be mixed with a 16% acetic acid solution to produce 141.78 ml of 63% solution?

118.99 mL of a 72% acetic acid solution must be mixed with 22.79 mL of a 16% acetic acid solution

Step-by-step explanation:

Let

x ----> milliliters of 72% acetic acid solution

y ----> milliliters of 16% acetic acid solution

we know that

----> equation A

Change the percentages to their decimal equivalents

so

----> equation B

Solve the system of equations by graphing

Remember that the solution of the system is the intersection point both graphs

using a graphing tool

The intersection point is (118.99,22.79)

see the attached figure

therefore

118.99 mL of a 72% acetic acid solution must be mixed with 22.79 mL of a 16% acetic acid solution

where are the images of the functions i can only see the question you typed.

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.