Acircle has the equation x2+y2−14x−18y+105=0.
what is the equation of the circle in standard f...
Mathematics, 21.01.2020 07:31 drdeb7766
Acircle has the equation x2+y2−14x−18y+105=0.
what is the equation of the circle in standard form, the location of its center, and the length of its radius?
the equation of the circle is (x+7)2+(y+9)2=25; the center is at (−7,−9), and the radius is 5 units.
the equation of the circle is (x+7)2+(y+9)2=89; the center is at (−7,−9), and the radius is 89−−√ units.
the equation of the circle is (x−7)2+(y−9)2=415; the center is at (7,9), and the radius is 415−−−√ units.
the equation of the circle is (x−7)2+(y−9)2=25; the center is at (7,9), and the radius is 5 units.
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