Question 10
10 points
the area of the rectangle is 22 m2,
3x + 1
part a: write an equation for the area of the rectangle. express your answer as a quadratic equation set equal to zero
part b: x=
part c: the width of the rectangle is
meters.

Step-by-step explanation:

A = L * W

A = 22

L = 2x + 1

W = 3x + 1

now we sub

22 = (2x + 1)(3x + 1)

22 = 6x^2 + 2x + 3x + 1

22 = 6x^2 + 5x + 1

6x^2 + 5x + 1 - 22 = 0

6x^2 + 5x - 21 = 0 <part A

(3x + 7)(2x - 3) = 0

3x + 7 = 0          2x - 3 = 0

3x = -7               2x = 3

x = -7/3              x = 3/2

I believe that x = -7/3 is an extraneous solution because when u plug it into ur length and width u get a negative numberand I dont think the sides of ur rectangle have negative values, however, it does work in ur equation and it equals 22 when multiplied...so I am not 100% sure

length = 2x + 12(3/2) + 13 + 1 = 4

width = 3x + 13(3/2) + 19/2 + 19/2 + 2/2 = 11/2 (or 5.5) meters <===

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.

1.30

step-by-step explanation: