Aweather balloon is launched from the ground at a spot 250 yards from a 65 foot royal palm tree . what is the minimal angle of elevation at which the balloon must take off in order to avoid hitting the tree? assume that the balloon flies in a straight line and the angle of elevation stays constant.

Angle of elevation at which the balloon must take off in order to avoid hitting the tree is 5 degrees

Step-by-step explanation:

Given:

The height of the tree  = 65 foot

The distance between the tree and the spot from which the balloon is launched = 250 yards

To find:

The angle of elevation at which the balloon must take off in order to avoid hitting the tree = ?

Solution:

Converting the yards to feet

1 yards = 3 feet

250 yards = 3 x 250 = 750 yards

Refer the below figure, The angle x is the angle of elevation at which the the ball must be thrown so that it does not Hit the tree

Substituting the values

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction