Cars a and b are traveling from town x to town y on the same route at constant speeds. car a is initially behind car b, and car a’s speed is 1.25 times car b’s speed. car a passes car b at 1: 30 pm. at 3: 15 pm, car a reaches town y, and at that moment, car b is still 35 miles away from town y. what is the speed of car a?
(a) 60 mph
(b) 75 mph
(c) 80 mph
(d) 96 mph
(e) 100 mph

do you have the measurements?

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

if i put something wrong your not gonna like it so rather not say nothing.