The law of cosines for abc can be set up as 52 = 72 + 32 – 2(7)(3)cos(b). what could be true about abc? law of cosines: a2 = b2 + c2 – 2bccos(a) a = 5 and c = 7 a = 3 and c = 3 b = 7 and c = 5 b = 5 and c = 3

b = 5 and c = 3

Step-by-step explanation:

The law of cosines states:  

b^2 = a^2 + c^2 - 2*a*c*cos(B)

where B is the angle opposite to side b, and a and c are the other two sides of the triangle.

From data we know that

5^2 = 7^2 + 3^2 – 2*7*3*cos(B)

So, a = 7, c = 3 and b = 5

i dont know

step-by-step explanation: