susan and abe shared comic books of 3 to 5. if abe had 14 more comic books than susan, how many comic books did they have in all?

The number of comic books did they have in all   = 56

Step-by-step explanation:

The ratio of comics with Susan : Abe = 3 : 5

Let us assume the common factor on this ratio = m

So, the number of comics Susan has  = 3 m

The number of comics Abe has  = 5 m

Also, given:  Abe had 14 more comic books than Susan

So, the number of comics Abe had  = 14 + 3 m

⇒  5 m  =  3 m + 14

or,   2 m = 14, or m = 7

So, the number of books Susan has = 3 m = 3 x 7 = 21 books

The number of books Abe has  = 5 m = 5 x 7 = 35

So, the book they have in all = 21 +  35 = 56

so what is the question

step-by-step explanation:

1/800 is the right answer