Math problem is on the attached picture.

the consecutive integars is 11,12,13,14,15

Step-by-step explanation:

then it says the sum of the first and 4 times the third = 60 less than 3 times the sum of the second, fourth and fifth

60 less than 3 times the sum of the second, fourth and fifth means that 3 times the sum of the second, fourth and fifth minus 60

y+ 4(y+2) = 3{ (y +1) +(y+3) + (y+4)} -60

y + 4y + 8 =3[ y +1 + y + 3 +y+4} - 60

5y +8=3(y+y+y+1+3+4)-60

5y+8=3(3y+8)-60

5y+8=9y+24-60

5y+8=9y-36

5y+8-8=9y-36-8

5y=9y-44

5y-9y=9y-9y-44

-4y=-44

-4y/-4=-44/-4 ( minus divided by minus is plus

y = 11

1 and 2

step-by-step explanation:

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point