Anumber consisting of two digits exceeds 4 times the sum of the digits by 3 .if 27 is added to the number, the place of the digits of the number are interchanged, find the number.

  47

Step-by-step explanation:

We can take x to represent the 10s digit and y the ones digit. Then we have ...

  (10x +y) - 4(x+y) = 3. . . . . a number exceeds 4 times the digit sum by 3

  (10x +y) +27 = (10y +x) . . . . . adding 27 swaps the digits

Simplifying these equations to standard form gives ...

  2x - y = 1

  x - y = -3

Subtracting the second equation from the first gives ...

  x = 4

  y = 2x -1 = 7

The number is 47.

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point