What are the solutions to the inequality (x-3)(x+5) < _ 0

(x-3)(x-5)<_0

If any individual factor on the left side of the equation is equal to 00, the entire expression will be equal to 00.  

x−3=0x-3=0  

x+5=0x+5=0  

Set the first factor equal to 00 and solve.  

x=3x=3  

Set the next factor equal to 00 and solve.  

x=−5x=-5  

Consolidate the solutions.  

x=3,−5x=3,-5  

Use each root to create test intervals.  

x<−5x<-5  

−5<x<3-5<x<3  

x>3x>3  

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.  

x<−5x<-5 False  

−5<x<3-5<x<3 True  

x>3x>3 False  

The solution consists of all of the true intervals.  

−5<x<3-5<x<3  

The result can be shown in multiple forms.  

Inequality Form:  

−5<x<3-5<x<3  

Interval Notation:  

(−5,3)

1; 35 is the ratio

step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.