The table below shows the weights of three insects
insect
mass (in grams)
butterfly
1.1629

beetle
4.030

praying mantis
2.400

a butterfly and beetle are placed on one side of a balance scale. a praying mantis is placed on the other
side of the balance scale. what is the difference in the mass of the live sides of the balance? round
your answer to the hundredths place.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

60%

answer: what statements

step-by-step explanation if you write the statements down then i could you.