Samples of skin experiencing desquamation are analyzed for both moisture and melanin content. the results from 100 skin samples are as follows: melanin content high low moisture high 13 10 content low 47 30 let a denote the event that a sample has low melanin content, and let b denote the event that a sample has high moisture content. determine the following probabilities. round your answers to three decimal places (e. g. 98.765).
a) p(a)
b) p(b)
c) p (a|b)
d) p (ba)

a. 0.40   b. 0.23  c . 0.435   d . 0.25

Step-by-step explanation:

                                   melanin      content    Total

                                            high   low

moisture   high                     13      10                23

content    low                       47      30                77

 Total                                   60      40               100

Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.

a) Total skin samples has low melanin content = 10+30=40

P(A)=

b) Total skin samples has high moisture content = 13+10=23

P(B) =

c) A ∩ B =  Total skin samples has both low melanin content and high moisture content =10

P(A ∩ B) =

Using conditional probability formula ,

d)  

a² + b²= c²

24² + 7² = c²

c= 25

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9