384
=96
858 -434
company a:
m a
4-2
a(x)=212x + b
434-212(2)+b
10=b
424
1,422 - 1,038
- - 212 company b: m="
6-2
b(x)=96x + b
1,038 = 96(2)+b
846=b
+ 10
1 b(x)=96x + 846
212x + 10-96x + 846
116x -836
x-72
how do you find the correct point for company b

The average daily maximum temperature for laura’s hometown can be modeled by the function f(x)=4.5sin(πx/6)+11.8 , where f(x) is the temperature in °c and x is the month. x = 0 corresponds to january.what is the average daily maximum temperature in may? round to the nearest tenth of a degree if needed.use 3.14 for π .