There are 3 people in a room, and we are curious whether two of them have their birthday in the same month. we record the triplet that describes the month of birthday for each person. e. g. (oct, jan, jul) is one possible triplet/outcome. (since each month applies to a specific person, (oct, jan, jul) is not the same as (jan, jul, oct) and so order is important.) a. how many possible outcomes are there? b. in how many of these outcomes, all three people have their birthday in different months? c. in how many of these outcomes, at least two people have their birthday in the same month?

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

stethere all not eveanp-by-step explanation: