Assume that iq scores are normally distributed with a mean of 100 and a standard deviation of 16. if 100 people are randomly selected, find the probability that their mean iq score is greater than 103. (rounded to the four decimal places)

0.03 is  the probability that for the sample mean IQ score is greater than 103.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 16

Sample size, n = 100

We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.

Formula:

Standard error due to sampling =

P( mean IQ score is greater than 103)

P(x > 103)

Calculation the value from standard normal z table, we have,  

0.03 is  the probability that for the sample mean IQ score is greater than 103.

7

step-by-step explanation:

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13