In general, how do the hypotheses for chi-square tests of independence differ from those for chi-square tests of homogeneity

chi-square test independence is evaluate whether one variable is related to other variable or not. it checks for independency.

chi-square test for homogeneity -  it is used to identify the homogeneity of one variable across the given population.

Step-by-step explanation:

chi-square test - although this test is also dealt with classified data, there is a difference between the chi-square test on independence and the chi-square test of homogeneity

chi-square test independence is evaluate whether one variable is related to other variable or not. it checks for independency.

chi-square test for homogeneity -  it is used to identify the homogeneity of one variable across the given population.

the answer is a

step-by-step explanation:

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x