Construct a tangent to a circle through a point outside the circle using the construction tool. insert
a screenshot of the construction here. alternatively, construct a tangent to a circle through a point
outside the circle by hand using a compass and straightedge. leave all circle and arc markings.
(10 points)

what's that

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

the answer is 1/4

step-by-step explanation:

answer: you need to organize this better it does not make sense.

step-by-step explanation: ?