Michael beasley is shooting free throws. making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 75%, percent of the time. what is the probability of michael beasley making all of his next 4 free throw attempts?
a. 75^8
b. 375^4
c. 75^4
d. 1.50^2

C.  

Step-by-step explanation:

Let x be the binomial variable that denotes the number of makes.

Since each throw is independent from the other throw , so we can say it follows Binomial distribution .

So

Binomial distribution formula: The probability of getting x success in n trials :

, where p = probability of getting success in each trial.

Then, the probability of Michael Beasley making all of his next 4 free throw attempts will be :

Thus, the probability of Michael Beasley making all of his next 4 free throw attempts is

Hence, the correct answer is C.  .

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

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step-by-step explanation: vsfdvsfvd