Assume that a random sample is used to estimate a population proportion p. find the margin of error e that corresponds to the given statistics and confidence level. nbsp 90 % confidence; the sample size is 3200 comma of which 15 % are successes 90% confidence; the sample size is 3200, of which 15% are successes the margin of error eequals=nothing. (round to four decimal places as needed.)

The margin of error E = 0.0104

Step-by-step explanation:

The formula to find the margin of error that corresponds to the given statistics and confidence level for population proportion is given by :-

, where

n= Sample size

= Sample proportion

z* = critical value.

As per given , we have

n= 3200

Confidence level : 90%

The critical z-value for 90% confidence is z* = =1.645[By z-table]

Substitute all values in the formula , we get

Hence, the margin of error E = 0.0104

9

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