Aparcel of land is 8 ft longer than it is wide. each diagonal from one corner to the opposite corner is 232 ft long.
what are the dimensions of the parcel?
width?
length?

width = 160 ft  and length = 168 ft

Step-by-step explanation:

A parcel of land is 8 ft longer than it is wide.

diagonal is 232 ft long.

Let 'w' be the width of the parcel and w+8 is the length of the parcel

Diagonal is the hypotenuse . use Pythagorean theorem to find out width 'w'

c=232 , a= w+8 and b= w

Subtract 53824 from both sides

Apply quadratic formula

width = 160  and length = 160+8= 168

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation:

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft