Determine the upper limit of a 95% confidence level estimate of the population proportion when the sample size is 200 customers, 35 of whom respond yes to a survey.

0.228

Step-by-step explanation:

We know that the formula to find the upper limit of confidence interval for population proportion is given by :-

, where

n= Sample size

= Sample proportion

z* = critical value.

Let p be the  proportion of customers who responds yes to a survey.

As per given , we have

n= 200

Confidence level : 95%

The critical z-value for 95% confidence is z* = 1.96  [ from z-table]

Substitute all values in the formula , we get

Hence, the upper limit of a 95% confidence level estimate of the population proportion is 0.228.

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation: