Solve by elimination
x-2y=12
5x+3y=-44

The solution is x = -4 and y = -8

Solution:

Given system of equations are:

x - 2y = 12 eqn 1

5x + 3y = -44 eqn 2

We have to solve the system of equations by elimination

Multiply eqn 1 by 3

3(x - 2y = 12)

3x - 6y = 36 eqn 4

Multiply eqn 2 by 2

2(5x + 3y = -44)

10x + 6y = -88 eqn 5

Add eqn 4 and eqn 5

3x - 6y = 36

10x + 6y = -88

( + )

10x + 3x - 6y + 6y = 36 - 88

13x = 36 - 88

13x = -52

Substitute x = -4 in eqn 1

-4 - 2y = 12

-2y = 12 + 4

-2y = 16

Thus the solution is x = -4 and y = -8

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|

a

step-by-step explanation: