Find the first 4 terms of this equation, f(n) = f(n-1) + 5 f(1) = -2

Step-by-step explanation:

We have,

f(n) = f(n - 1) + 5

and f (1) = - 2               (1)

To find, the first four terms of the given equation = ?

Put n = 2, 3, 4, 5,

Put n = 2, we get

f(2) = f(2 - 1) + 5 = f(1) + 5

Using (1), we get

f(2)  = - 2 + 5 = 3         (2)

Put n = 3, we get

f(3) = f(3 - 1) + 5 = f(2) + 5

Using (2), we get

f(3)  = 3 + 5 = 8           (3)

Put n = 4, we get

f(4) = f(4 - 1) + 5 = f(3) + 5

Using (3), we get

f(4)  = 8 + 5 = 13         (4)

Put n = 5, we get

f(5) = f(5 - 1) + 5 = f(4) + 5

Using (4), we get

f(5)  = 13 + 5 = 18        

Thus, the first fourth term of the equation are 3, 8, 13 and 18.

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are