I'm confused by this problem and don't know where to go from here, any would be appreciated.

integral from 0 to 1 of f(t) dt = 28, find integral from -1.5 to -1 of f(3 + 2t) dt.

i set u = 3 + 2t and therefore du = 2 dt, then ended up with 1/2 * the integral from -1.5 to -1 of f(u) du.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

the answer is 54 sq. ft. i just did this question, on odyssey ware, and it was right. make brainliest.

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6