Mrs. kwok is 6 years more than 3 times as old as her son. six years ago, she was 14 year more than twice as old as her son was then. find both of their ages.

Mrs. Kwok is 42.

Her daughter is 12.

Step-by-step explanation: Mrs. Knok's age = x    Daughter's age = y

x-6=3y   ,   (x-8)+2=9(y-8)    

                    x-6=9y-72

(x-6)-(x-6) = (9y-72)-(3y)                                 x-6=3(12)

0 = 6y-72                                                        x-6=36

6y=72                                                              x=42

y=12

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.