Seven times the smaller of two numbers added with two times the larger number is 635. while seven times the larger number decreased by two times the smaller number is 871. find the two numbers

Step-by-step explanation:

x = smaller number, y = bigger number

7x + 2y = 635

7y - 2x = 871rearrange...-2x + 7y = 871

7x + 2y = 635multiply by 2

-2x + 7y = 871...multiply by 7

14x + 4y = 1270 (result of multiplying by 2)

-14x + 49y = 6097 (result of multiplying by 7)

add

53y = 7367

y = 7367/53

y = 139

7x + 2y = 635

7x + 2(139) = 635

7x + 278 = 635

7x = 635 - 278

7x = 357

x = 357/7

x = 51

solution : x = 51 and y = 139 or (51,139)

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.