i will give brainliest

in the figure below, ∠dec ≅ ∠dce, ∠b ≅ ∠f, and segment df is congruent to segment bd. point c is the point of intersection between segment ag and segment bd while point e is the point of intersection between segment ag and segment df.

*look at image attached*

prove δabc ≅ δgfe.

∠ABC ≅ ∠DEC

∠DEC = ∠GEF

thus:

∠ABC = ∠GEF

∠GFE ≅ ∠DCE

∠DCE = ∠ACB

thus:

∠ACB = ∠GFE

If two of their angles are equal, then the third angle must also be equal, because angles of a triangle always add to make 180°.

thus: ΔABC ∼ ΔGEF by AA similar triangle postulate

I hope this helps

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

answer: 0.1,0.85

step-by-step explanation: