Arectangular room is twice as long as its breadth and its peimeter is 540 m. find the number of bricks of size 20 cm ×12cm to pave the room. if the rate of cost of bricka is rs. 950 per 1000, find the cost of paving the room.

Step-by-step explanation:

breadth = x

length = 2x

Perimeter = 540m

2*( length + breadth ) = 540

2 *(2x + x) = 540

3x = 540/2

3x = 270

x = 270/3

x = 90 m

Breadth = 90m = 90 *100 = 9000 cm

Length = 2*90 = 180 m = 180 * 100 = 18000 cm

No.of bricks = Area of room/ area of one brick

= 9000 * 18000 / 20 * 12

= 675000 bricks

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

12.5 feet

step-by-step explanation: