The member of the student council are selling raffle tickets. the school decides that the top three raffle ticket sellers will share portion of the profits. the second place winner will receive 8 more dollars then the third place. the first place seller will receive twice as much as the second place seller. the profit portion they will share is $ 104. how much will each of the top three sellers receive?

the first place seller receives $56

The second place seller receives $28

The third place seller receives $20

Step-by-step explanation:

Let x represent the amount that the first place seller would receive.

Let y represent the amount that the second place seller would receive.

Let z represent the amount that the third place seller would receive.

The second place winner will receive 8 more dollars than the third place winner. This means that

z = y - 8

The first place seller will receive twice as much as the second place seller. It means that

x = 2y

The profit portion they will share is $ 104. It means that

x + y + z = 104 - - - - - - - - - - - 1

Substituting z = y - 8 and x = 2y into equation 1, it becomes

2y + y + y - 8 = 104

4y = 104 +8 = 112

y = 112/4 = 28

x = 2x = 2 × 28

x = 56

z = y - 8 = 28 - 8

z = 20

step-by-step explanation:

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!